diff --git a/docs/api.rst b/docs/api.rst
index cedbd4aa2..5b30e6bd1 100644
--- a/docs/api.rst
+++ b/docs/api.rst
@@ -1230,54 +1230,52 @@ It's also possible to embed `Materialized Views <https://www.postgresql.org/docs
 Embedding Views containing Joins
 --------------------------------
 
-The same embedding rules applies to views with joined tables, that is, the column of any table participating in the join with a **foreign key** definition must be present in the view.
+On views that contain joins, PostgREST will infer the joined tables' foreign keys based on the sources of the view columns.
 
-For instance, let's create a view called ``film_competition_view`` that will join three tables:
+For instance, let's create a view called ``detailed_nominations_view`` that will join three tables:
 
 .. code-block:: postgres
 
-  CREATE VIEW film_competition_view AS
+  CREATE VIEW detailed_nominations_view AS
   SELECT
-   films.title as film_title
+     films.title as film_title
    , competitions.name as competition_name
+   , rank
    , film_id
-  FROM
-   nominations
-   JOIN films ON films.id = nominations.film_id
-   JOIN competitions ON competitions.id = nominations.competition_id;
+  FROM nominations
+  JOIN films ON films.id = nominations.film_id
+  JOIN competitions ON competitions.id = nominations.competition_id;
 
 The view can be embedded with the table ``films`` because it has the ``film_id`` column from the ``nominations`` table, which has a relationship with ``films``.
 
-But what if you want to embed the view with the ``actors`` table? The ``film_id`` column alone will not allow it since it belongs to ``nominations``, which doesn't have a relationship to ``actors``. In this case, you need to select the ``films.id`` column from the ``films`` table, which has a many-to-many relationship with ``actors``.
+But what if you want to embed the view with the ``actors`` table? The ``film_id`` column alone will not allow it since it belongs to ``nominations``, which doesn't have a relationship to ``actors``. In this case, you need to select the ``id`` column from the ``films`` table, which has a many-to-many relationship with ``actors``.
 
 .. code-block:: postgres
 
-  CREATE VIEW film_competition_view AS
+  CREATE VIEW detailed_nominations_view AS
   SELECT
-   films.title as film_title
+     films.title as film_title
    , competitions.name as competition_name
+   , rank
    -- To keep the relationship with the films table, this column is renamed
    , film_id as nominations_film_id
    -- Adding this column allows the relationships we want
    , films.id as film_id
-  FROM
-   nominations
-   JOIN films ON films.id = nominations.film_id
-   JOIN competitions ON competitions.id = nominations.competition_id;
+  FROM nominations
+  JOIN films ON films.id = nominations.film_id
+  JOIN competitions ON competitions.id = nominations.competition_id;
 
-Now the view can embed both the ``films`` and ``actors`` tables:
+Now we can embed both the ``films`` and ``actors`` tables:
 
 .. tabs::
 
   .. code-tab:: http
 
-    GET /film_competition_view?select=film_title,films(language),actors(last_name,first_name)&competition_name=ilike.bafta HTTP/1.1
+    GET /detailed_nominations_view?select=film_title,rank,films(language),actors(last_name,first_name)&competition_name=ilike.bafta HTTP/1.1
 
   .. code-tab:: bash Curl
 
-    curl "http://localhost:3000/film_competition_view?select=film_title,films(language),actors(last_name,first_name)&competition_name=ilike.bafta"
-
-As seen above, it is important to verify that the column in the view has the foreign key to the table you want to embed.
+    curl "http://localhost:3000/detailed_nominations_view?select=film_title,rank,films(language),actors(last_name,first_name)&competition_name=ilike.bafta"
 
 .. _embedding_view_chains: